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I think this should be listed as a Floribunda rather than Hybrid Tea. The references and comments describe it as such.
:-)
~Christopher
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#1 of 2 posted
2 JAN 20 by
 jedmar
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You are right, it seems that the ARS class is incorrect
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All the ARS publications of which I am aware say 'Passionate Kisses' is a floribunda.
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The US patent application (12/923,828) was abandoned 12/26/2013. The application lists Alain A. Meilland as the inventor. The application, and all current ARS publications of which I am aware, say the rose is a floribunda.
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Yep. Passionate Kisses has always been a florrie in the States.
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According to US Plant Patent 6,199 (Minwco), the pollen parent is Black Jack ((US Plant Patent 5,671), not Black Jade.
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The variety is covered by US Plant Patent 34553. The patent uses the variety name 'Vanilla Vixen.' However, the name was changed before the rose was introduced . 'Vanilla Vixen' was never used in commerce. The variety just received an American Garden Rose Selection (AGRS) for the north central, northwest, and southwest regions.
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#1 of 1 posted
9 MAY by
jedmar
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Listings merged, thank you!
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